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12046242751441 is a prime number
BaseRepresentation
bin1010111101001011110000…
…0001010010001111010001
31120122121110100222021100021
42233102330001102033101
53034331201121021231
641341544552423441
72352212060633563
oct257227401221721
946577410867307
1012046242751441
113924867a96458
1214267863a7b81
13694c56c131c2
142d9081309333
1515d53c9e1811
hexaf4bc0523d1

12046242751441 has 2 divisors, whose sum is σ = 12046242751442. Its totient is φ = 12046242751440.

The previous prime is 12046242751421. The next prime is 12046242751453. The reversal of 12046242751441 is 14415724264021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7225236480400 + 4821006271041 = 2687980^2 + 2195679^2 .

It is a cyclic number.

It is not a de Polignac number, because 12046242751441 - 211 = 12046242749393 is a prime.

It is a super-3 number, since 3×120462427514413 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (12046242751421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6023121375720 + 6023121375721.

It is an arithmetic number, because the mean of its divisors is an integer number (6023121375721).

Almost surely, 212046242751441 is an apocalyptic number.

It is an amenable number.

12046242751441 is a deficient number, since it is larger than the sum of its proper divisors (1).

12046242751441 is an equidigital number, since it uses as much as digits as its factorization.

12046242751441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 430080, while the sum is 43.

The spelling of 12046242751441 in words is "twelve trillion, forty-six billion, two hundred forty-two million, seven hundred fifty-one thousand, four hundred forty-one".