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12050145333335 = 513671763005901
BaseRepresentation
bin1010111101011010010010…
…1000011101000001010111
31120122222112100100222021102
42233112210220131001113
53034412144201131320
641343432122340315
72352410556220424
oct257264450350127
946588470328242
1012050145333335
11392648a991a4a
12142749535a69b
136954295b6365
142d9331740d4b
1515d6ba422175
hexaf5a4a1d057

12050145333335 has 8 divisors (see below), whose sum is σ = 14470752443616. Its totient is φ = 9633064237600.

The previous prime is 12050145333307. The next prime is 12050145333349. The reversal of 12050145333335 is 53333354105021.

12050145333335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12050145333335 - 242 = 7652098822231 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 881496116 + ... + 881509785.

It is an arithmetic number, because the mean of its divisors is an integer number (1808844055452).

Almost surely, 212050145333335 is an apocalyptic number.

12050145333335 is a deficient number, since it is larger than the sum of its proper divisors (2420607110281).

12050145333335 is a wasteful number, since it uses less digits than its factorization.

12050145333335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1763007273.

The product of its (nonzero) digits is 243000, while the sum is 38.

Adding to 12050145333335 its reverse (53333354105021), we get a palindrome (65383499438356).

The spelling of 12050145333335 in words is "twelve trillion, fifty billion, one hundred forty-five million, three hundred thirty-three thousand, three hundred thirty-five".

Divisors: 1 5 1367 6835 1763005901 8815029505 2410029066667 12050145333335