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12050172013 = 111095470183
BaseRepresentation
bin10110011100011111…
…10000100001101101
31011002210112011102011
423032033300201231
5144134321001023
65311421001221
7604420525555
oct131617604155
934083464364
1012050172013
11512400a650
1224036b3211
1311a06802c9
1482455c165
154a7d8150d
hex2ce3f086d

12050172013 has 4 divisors (see below), whose sum is σ = 13145642208. Its totient is φ = 10954701820.

The previous prime is 12050172011. The next prime is 12050172047. The reversal of 12050172013 is 31027105021.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12050172013 - 21 = 12050172011 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12050172011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 547735081 + ... + 547735102.

It is an arithmetic number, because the mean of its divisors is an integer number (3286410552).

Almost surely, 212050172013 is an apocalyptic number.

It is an amenable number.

12050172013 is a deficient number, since it is larger than the sum of its proper divisors (1095470195).

12050172013 is a wasteful number, since it uses less digits than its factorization.

12050172013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1095470194.

The product of its (nonzero) digits is 420, while the sum is 22.

Adding to 12050172013 its reverse (31027105021), we get a palindrome (43077277034).

The spelling of 12050172013 in words is "twelve billion, fifty million, one hundred seventy-two thousand, thirteen".

Divisors: 1 11 1095470183 12050172013