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1205041130 = 25120504113
BaseRepresentation
bin100011111010011…
…0111011111101010
310002222111102122222
41013310313133222
54431442304010
6315324114042
741601452306
oct10764673752
93088442588
101205041130
1156923a267
12297695922
1316286abb7
14b6082d06
1570bd4355
hex47d377ea

1205041130 has 8 divisors (see below), whose sum is σ = 2169074052. Its totient is φ = 482016448.

The previous prime is 1205041121. The next prime is 1205041171. The reversal of 1205041130 is 311405021.

It can be written as a sum of positive squares in 2 ways, for example, as 1102970521 + 102070609 = 33211^2 + 10103^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1205041099 and 1205041108.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60252047 + ... + 60252066.

Almost surely, 21205041130 is an apocalyptic number.

1205041130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1205041130 is a deficient number, since it is larger than the sum of its proper divisors (964032922).

1205041130 is a wasteful number, since it uses less digits than its factorization.

1205041130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 120504120.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 1205041130 is about 34713.7023378377. The cubic root of 1205041130 is about 1064.1445458409.

Adding to 1205041130 its reverse (311405021), we get a palindrome (1516446151).

The spelling of 1205041130 in words is "one billion, two hundred five million, forty-one thousand, one hundred thirty".

Divisors: 1 2 5 10 120504113 241008226 602520565 1205041130