Base | Representation |
---|---|
bin | 1010111101101001111101… |
… | …0100110000111001101111 |
3 | 1120200101101110112211112122 |
4 | 2233122133110300321233 |
5 | 3034444302410044403 |
6 | 41345405330023155 |
7 | 2352620030025245 |
oct | 257323724607157 |
9 | 46611343484478 |
10 | 12054351253103 |
11 | 39282490317a5 |
12 | 1428269a17abb |
13 | 695949a85693 |
14 | 2d9610178795 |
15 | 15d8647c0838 |
hex | af69f530e6f |
12054351253103 has 16 divisors (see below), whose sum is σ = 12738922860000. Its totient is φ = 11374798159872.
The previous prime is 12054351253097. The next prime is 12054351253111. The reversal of 12054351253103 is 30135215345021.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 12054351253103 - 210 = 12054351252079 is a prime.
It is a super-3 number, since 3×120543512531033 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12054351253123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 94221923 + ... + 94349771.
It is an arithmetic number, because the mean of its divisors is an integer number (796182678750).
Almost surely, 212054351253103 is an apocalyptic number.
12054351253103 is a deficient number, since it is larger than the sum of its proper divisors (684571606897).
12054351253103 is a wasteful number, since it uses less digits than its factorization.
12054351253103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 147434.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 12054351253103 its reverse (30135215345021), we get a palindrome (42189566598124).
The spelling of 12054351253103 in words is "twelve trillion, fifty-four billion, three hundred fifty-one million, two hundred fifty-three thousand, one hundred three".
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