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12055211626057 is a prime number
BaseRepresentation
bin1010111101101101001010…
…0110110100111001001001
31120200110121102111022100121
42233123102212310321021
53040003033134013212
641350030542503241
72352650245051225
oct257332246647111
946613542438317
1012055211626057
11392864a758726
121428469b94b21
13695a560b61c2
142d969253b785
1515d8b50c0d07
hexaf6d29b4e49

12055211626057 has 2 divisors, whose sum is σ = 12055211626058. Its totient is φ = 12055211626056.

The previous prime is 12055211626043. The next prime is 12055211626127. The reversal of 12055211626057 is 75062611255021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6983815721481 + 5071395904576 = 2642691^2 + 2251976^2 .

It is a cyclic number.

It is not a de Polignac number, because 12055211626057 - 27 = 12055211625929 is a prime.

It is not a weakly prime, because it can be changed into another prime (12055211626027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6027605813028 + 6027605813029.

It is an arithmetic number, because the mean of its divisors is an integer number (6027605813029).

Almost surely, 212055211626057 is an apocalyptic number.

It is an amenable number.

12055211626057 is a deficient number, since it is larger than the sum of its proper divisors (1).

12055211626057 is an equidigital number, since it uses as much as digits as its factorization.

12055211626057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252000, while the sum is 43.

The spelling of 12055211626057 in words is "twelve trillion, fifty-five billion, two hundred eleven million, six hundred twenty-six thousand, fifty-seven".