Base | Representation |
---|---|
bin | 10110011110100000… |
… | …00000011110010111 |
3 | 1011010222012212000212 |
4 | 23033100000132113 |
5 | 144203123431201 |
6 | 5313222000035 |
7 | 605013634304 |
oct | 131720003627 |
9 | 34128185025 |
10 | 12067014551 |
11 | 51325736a9 |
12 | 240927601b |
13 | 11a3cc94c7 |
14 | 8268a40ab |
15 | 4a95ababb |
hex | 2cf400797 |
12067014551 has 4 divisors (see below), whose sum is σ = 12702120600. Its totient is φ = 11431908504.
The previous prime is 12067014541. The next prime is 12067014569. The reversal of 12067014551 is 15541076021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12067014551 - 222 = 12062820247 is a prime.
It is a super-2 number, since 2×120670145512 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12067014541) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 317552996 + ... + 317553033.
It is an arithmetic number, because the mean of its divisors is an integer number (3175530150).
Almost surely, 212067014551 is an apocalyptic number.
12067014551 is a deficient number, since it is larger than the sum of its proper divisors (635106049).
12067014551 is an equidigital number, since it uses as much as digits as its factorization.
12067014551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 635106048.
The product of its (nonzero) digits is 8400, while the sum is 32.
The spelling of 12067014551 in words is "twelve billion, sixty-seven million, fourteen thousand, five hundred fifty-one".
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