Base | Representation |
---|---|
bin | 10001100100011100110… |
… | …111111010101010100001 |
3 | 11021102102201002121102222 |
4 | 101210130313322222201 |
5 | 124240143234333213 |
6 | 2322354102120425 |
7 | 153141521425223 |
oct | 21443467725241 |
9 | 4242381077388 |
10 | 1207370230433 |
11 | 426052023324 |
12 | 175bb5a20115 |
13 | 89b1550b0c3 |
14 | 426192da413 |
15 | 21616c87808 |
hex | 1191cdfaaa1 |
1207370230433 has 2 divisors, whose sum is σ = 1207370230434. Its totient is φ = 1207370230432.
The previous prime is 1207370230361. The next prime is 1207370230499. The reversal of 1207370230433 is 3340320737021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1165812553984 + 41557676449 = 1079728^2 + 203857^2 .
It is a cyclic number.
It is not a de Polignac number, because 1207370230433 - 220 = 1207369181857 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1207370230393 and 1207370230402.
It is not a weakly prime, because it can be changed into another prime (1207370235433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 603685115216 + 603685115217.
It is an arithmetic number, because the mean of its divisors is an integer number (603685115217).
Almost surely, 21207370230433 is an apocalyptic number.
It is an amenable number.
1207370230433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1207370230433 is an equidigital number, since it uses as much as digits as its factorization.
1207370230433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 63504, while the sum is 35.
Adding to 1207370230433 its reverse (3340320737021), we get a palindrome (4547690967454).
The spelling of 1207370230433 in words is "one trillion, two hundred seven billion, three hundred seventy million, two hundred thirty thousand, four hundred thirty-three".
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