Base | Representation |
---|---|
bin | 11011011101111111110100… |
… | …001001010010000001110001 |
3 | 120211202012012220212122102212 |
4 | 123131333310021102001301 |
5 | 111313312044122132213 |
6 | 1104534420144221505 |
7 | 34306064515065533 |
oct | 3335776411220161 |
9 | 524665186778385 |
10 | 120808641208433 |
11 | 3554772553a782 |
12 | 1167163560a895 |
13 | 525428a712919 |
14 | 21b9252cd1853 |
15 | de779b3a09a8 |
hex | 6ddff4252071 |
120808641208433 has 2 divisors, whose sum is σ = 120808641208434. Its totient is φ = 120808641208432.
The previous prime is 120808641208421. The next prime is 120808641208441. The reversal of 120808641208433 is 334802146808021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 69755787072049 + 51052854136384 = 8351993^2 + 7145128^2 .
It is a cyclic number.
It is not a de Polignac number, because 120808641208433 - 212 = 120808641204337 is a prime.
It is not a weakly prime, because it can be changed into another prime (120808641201433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60404320604216 + 60404320604217.
It is an arithmetic number, because the mean of its divisors is an integer number (60404320604217).
Almost surely, 2120808641208433 is an apocalyptic number.
It is an amenable number.
120808641208433 is a deficient number, since it is larger than the sum of its proper divisors (1).
120808641208433 is an equidigital number, since it uses as much as digits as its factorization.
120808641208433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1769472, while the sum is 50.
The spelling of 120808641208433 in words is "one hundred twenty trillion, eight hundred eight billion, six hundred forty-one million, two hundred eight thousand, four hundred thirty-three".
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