Base | Representation |
---|---|
bin | 1010111111111010000011… |
… | …0101011111011011000011 |
3 | 1120211002020010220120112212 |
4 | 2233332200311133123003 |
5 | 3041113012004041024 |
6 | 41415243434012335 |
7 | 2355456406105355 |
oct | 257764065373303 |
9 | 46732203816485 |
10 | 12093031315139 |
11 | 3942697a04915 |
12 | 14338638770ab |
13 | 6994a253bb58 |
14 | 2db43d3150d5 |
15 | 15e87a479a0e |
hex | affa0d5f6c3 |
12093031315139 has 2 divisors, whose sum is σ = 12093031315140. Its totient is φ = 12093031315138.
The previous prime is 12093031315121. The next prime is 12093031315147. The reversal of 12093031315139 is 93151313039021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12093031315139 - 216 = 12093031249603 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12093031315096 and 12093031315105.
It is not a weakly prime, because it can be changed into another prime (12093031315109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6046515657569 + 6046515657570.
It is an arithmetic number, because the mean of its divisors is an integer number (6046515657570).
Almost surely, 212093031315139 is an apocalyptic number.
12093031315139 is a deficient number, since it is larger than the sum of its proper divisors (1).
12093031315139 is an equidigital number, since it uses as much as digits as its factorization.
12093031315139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 65610, while the sum is 41.
The spelling of 12093031315139 in words is "twelve trillion, ninety-three billion, thirty-one million, three hundred fifteen thousand, one hundred thirty-nine".
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