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120994020450851 is a prime number
BaseRepresentation
bin11011100000101100011101…
…100110111110001000100011
3120212101220201022121220001012
4123200230131212332020203
5111324331223213411401
61105155515144531135
734325346422462252
oct3340543546761043
9525356638556035
10120994020450851
1135609304267349
12116a1550780aab
1352688c193a142
1421c41db2ac799
15dec4eae738bb
hex6e0b1d9be223

120994020450851 has 2 divisors, whose sum is σ = 120994020450852. Its totient is φ = 120994020450850.

The previous prime is 120994020450847. The next prime is 120994020450949. The reversal of 120994020450851 is 158054020499021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 120994020450851 - 22 = 120994020450847 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 120994020450851.

It is not a weakly prime, because it can be changed into another prime (120994020456851) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60497010225425 + 60497010225426.

It is an arithmetic number, because the mean of its divisors is an integer number (60497010225426).

Almost surely, 2120994020450851 is an apocalyptic number.

120994020450851 is a deficient number, since it is larger than the sum of its proper divisors (1).

120994020450851 is an equidigital number, since it uses as much as digits as its factorization.

120994020450851 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1036800, while the sum is 50.

The spelling of 120994020450851 in words is "one hundred twenty trillion, nine hundred ninety-four billion, twenty million, four hundred fifty thousand, eight hundred fifty-one".