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12100011000 = 2335373111069
BaseRepresentation
bin10110100010011011…
…11000001111111000
31011020021022020122120
423101031320033320
5144240100323000
65320401121240
7605564253000
oct132115701770
934207266576
1012100011000
11514a1603a0
122418329220
1311aaab032c
1482b013000
154ac4286a0
hex2d13783f8

12100011000 has 512 divisors, whose sum is σ = 48072960000. Its totient is φ = 2511936000.

The previous prime is 12100010983. The next prime is 12100011017. The reversal of 12100011000 is 11000121.

It is an interprime number because it is at equal distance from previous prime (12100010983) and next prime (12100011017).

It is a Harshad number since it is a multiple of its sum of digits (6).

It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.

It is a self number, because there is not a number n which added to its sum of digits gives 12100011000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 11318466 + ... + 11319534.

It is an arithmetic number, because the mean of its divisors is an integer number (93892500).

Almost surely, 212100011000 is an apocalyptic number.

12100011000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12100011000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24036480000).

12100011000 is an abundant number, since it is smaller than the sum of its proper divisors (35972949000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12100011000 is a wasteful number, since it uses less digits than its factorization.

12100011000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1125 (or 1097 counting only the distinct ones).

The product of its (nonzero) digits is 2, while the sum is 6.

Adding to 12100011000 its reverse (11000121), we get a palindrome (12111011121).

It can be divided in two parts, 121000 and 11000, that multiplied together give a cube (1331000000 = 11003).

The spelling of 12100011000 in words is "twelve billion, one hundred million, eleven thousand".