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121000222103113 is a prime number
BaseRepresentation
bin11011100000110010001111…
…010000011001011001001001
3120212102111201112010110121201
4123200302033100121121021
5111324431423324244423
61105202422403504201
734325656205606143
oct3340621720313111
9525374645113551
10121000222103113
11356109a69a94a1
12116a27a1688061
13526936c71b272
1421c4628badc93
15dec7606402ad
hex6e0c8f419649

121000222103113 has 2 divisors, whose sum is σ = 121000222103114. Its totient is φ = 121000222103112.

The previous prime is 121000222103039. The next prime is 121000222103119. The reversal of 121000222103113 is 311301222000121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120018751464249 + 981470638864 = 10955307^2 + 990692^2 .

It is an emirp because it is prime and its reverse (311301222000121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121000222103113 is a prime.

It is not a weakly prime, because it can be changed into another prime (121000222103119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60500111051556 + 60500111051557.

It is an arithmetic number, because the mean of its divisors is an integer number (60500111051557).

Almost surely, 2121000222103113 is an apocalyptic number.

It is an amenable number.

121000222103113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121000222103113 is an equidigital number, since it uses as much as digits as its factorization.

121000222103113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 121000222103113 its reverse (311301222000121), we get a palindrome (432301444103234).

The spelling of 121000222103113 in words is "one hundred twenty-one trillion, two hundred twenty-two million, one hundred three thousand, one hundred thirteen".