Base | Representation |
---|---|
bin | 10001100110111010011… |
… | …101000111001101010011 |
3 | 11021200020221211020001101 |
4 | 101212322131013031103 |
5 | 124311102041112201 |
6 | 2323512303245231 |
7 | 153264163222066 |
oct | 21467235071523 |
9 | 4250227736041 |
10 | 1210014004051 |
11 | 4271893a65a6 |
12 | 1766132a9817 |
13 | 8a1471693a8 |
14 | 427ca4948dd |
15 | 2171de12d01 |
hex | 119ba747353 |
1210014004051 has 2 divisors, whose sum is σ = 1210014004052. Its totient is φ = 1210014004050.
The previous prime is 1210014004033. The next prime is 1210014004159. The reversal of 1210014004051 is 1504004100121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1210014004051 - 221 = 1210011906899 is a prime.
It is not a weakly prime, because it can be changed into another prime (1210014008051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605007002025 + 605007002026.
It is an arithmetic number, because the mean of its divisors is an integer number (605007002026).
Almost surely, 21210014004051 is an apocalyptic number.
1210014004051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210014004051 is an equidigital number, since it uses as much as digits as its factorization.
1210014004051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 160, while the sum is 19.
Adding to 1210014004051 its reverse (1504004100121), we get a palindrome (2714018104172).
The spelling of 1210014004051 in words is "one trillion, two hundred ten billion, fourteen million, four thousand, fifty-one".
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