Base | Representation |
---|---|
bin | 1011000000010100100010… |
… | …1110110110111110110001 |
3 | 1120211202120210000111120111 |
4 | 2300011020232312332301 |
5 | 3041222043114204314 |
6 | 41422421244341321 |
7 | 2356130553320311 |
oct | 260051056667661 |
9 | 46752523014514 |
10 | 12100143116209 |
11 | 3945707380265 |
12 | 1435109544841 |
13 | 69a066a5ab75 |
14 | 2db915a55441 |
15 | 15eb449c9ec4 |
hex | b0148bb6fb1 |
12100143116209 has 2 divisors, whose sum is σ = 12100143116210. Its totient is φ = 12100143116208.
The previous prime is 12100143116197. The next prime is 12100143116267. The reversal of 12100143116209 is 90261134100121.
12100143116209 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10589817640000 + 1510325476209 = 3254200^2 + 1228953^2 .
It is a cyclic number.
It is not a de Polignac number, because 12100143116209 - 223 = 12100134727601 is a prime.
It is not a weakly prime, because it can be changed into another prime (12100143111209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050071558104 + 6050071558105.
It is an arithmetic number, because the mean of its divisors is an integer number (6050071558105).
Almost surely, 212100143116209 is an apocalyptic number.
It is an amenable number.
12100143116209 is a deficient number, since it is larger than the sum of its proper divisors (1).
12100143116209 is an equidigital number, since it uses as much as digits as its factorization.
12100143116209 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 31.
The spelling of 12100143116209 in words is "twelve trillion, one hundred billion, one hundred forty-three million, one hundred sixteen thousand, two hundred nine".
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