Base | Representation |
---|---|
bin | 11011100000110011111001… |
… | …111000111010101010111001 |
3 | 120212102200100012110102210202 |
4 | 123200303321320322222321 |
5 | 111324444104321010243 |
6 | 1105203320112251545 |
7 | 34326051431116652 |
oct | 3340637170725271 |
9 | 525380305412722 |
10 | 121002011110073 |
11 | 35611734834945 |
12 | 116a3000840bb5 |
13 | 526959625c772 |
14 | 21c4758624529 |
15 | dec8177264b8 |
hex | 6e0cf9e3aab9 |
121002011110073 has 2 divisors, whose sum is σ = 121002011110074. Its totient is φ = 121002011110072.
The previous prime is 121002011109949. The next prime is 121002011110103. The reversal of 121002011110073 is 370011110200121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 118232306347024 + 2769704763049 = 10873468^2 + 1664243^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121002011110073 is a prime.
It is not a weakly prime, because it can be changed into another prime (121002011110873) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60501005555036 + 60501005555037.
It is an arithmetic number, because the mean of its divisors is an integer number (60501005555037).
Almost surely, 2121002011110073 is an apocalyptic number.
It is an amenable number.
121002011110073 is a deficient number, since it is larger than the sum of its proper divisors (1).
121002011110073 is an equidigital number, since it uses as much as digits as its factorization.
121002011110073 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 20.
Adding to 121002011110073 its reverse (370011110200121), we get a palindrome (491013121310194).
The spelling of 121002011110073 in words is "one hundred twenty-one trillion, two billion, eleven million, one hundred ten thousand, seventy-three".
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