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121002113 is a prime number
BaseRepresentation
bin1110011011001…
…01100010000001
322102200112200202
413031211202001
5221434031423
620001254545
72666333561
oct715454201
9272615622
10121002113
1162336751
1234634455
131c0b80ab
14120dada1
15a952728
hex7365881

121002113 has 2 divisors, whose sum is σ = 121002114. Its totient is φ = 121002112.

The previous prime is 121002109. The next prime is 121002121. The reversal of 121002113 is 311200121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101747569 + 19254544 = 10087^2 + 4388^2 .

It is a cyclic number.

It is not a de Polignac number, because 121002113 - 22 = 121002109 is a prime.

It is a super-2 number, since 2×1210021132 = 29283022700929538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121002094 and 121002103.

It is not a weakly prime, because it can be changed into another prime (121002613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60501056 + 60501057.

It is an arithmetic number, because the mean of its divisors is an integer number (60501057).

Almost surely, 2121002113 is an apocalyptic number.

It is an amenable number.

121002113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121002113 is an equidigital number, since it uses as much as digits as its factorization.

121002113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 121002113 is about 11000.0960450352. The cubic root of 121002113 is about 494.6116233943.

Adding to 121002113 its reverse (311200121), we get a palindrome (432202234).

The spelling of 121002113 in words is "one hundred twenty-one million, two thousand, one hundred thirteen".