12100243313343 has 4 divisors (see below), whose sum is σ = 16133657751128. Its totient is φ = 8066828875560.

The previous prime is 12100243313317. The next prime is 12100243313357. The reversal of 12100243313343 is 34331334200121.

12100243313343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 12100243313343 - 2²¹ = 12100241216191 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12100243313343.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12100243313393) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2016707218888 + ... + 2016707218893.

It is an arithmetic number, because the mean of its divisors is an integer number (4033414437782).

Almost surely, 2^{12100243313343} is an apocalyptic number.

12100243313343 is a deficient number, since it is larger than the sum of its proper divisors (4033414437785).

12100243313343 is an equidigital number, since it uses as much as digits as its factorization.

12100243313343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4033414437784.

The product of its (nonzero) digits is 15552, while the sum is 30.

Adding to 12100243313343 its reverse (34331334200121), we get a palindrome (46431577513464).

The spelling of 12100243313343 in words is "twelve trillion, one hundred billion, two hundred forty-three million, three hundred thirteen thousand, three hundred forty-three".