Base | Representation |
---|---|
bin | 1011000000010101001011… |
… | …0000001010101101100011 |
3 | 1120211210000111100122011111 |
4 | 2300011102300022231203 |
5 | 3041222414133400311 |
6 | 41422450051524151 |
7 | 2356134664266001 |
oct | 260052260125543 |
9 | 46753014318144 |
10 | 12100311231331 |
11 | 3945793265684 |
12 | 14351558b9657 |
13 | 69a09283027b |
14 | 2db9300d7a71 |
15 | 15eb54636d21 |
hex | b0152c0ab63 |
12100311231331 has 2 divisors, whose sum is σ = 12100311231332. Its totient is φ = 12100311231330.
The previous prime is 12100311231311. The next prime is 12100311231343. The reversal of 12100311231331 is 13313211300121.
It is a strong prime.
It is an emirp because it is prime and its reverse (13313211300121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12100311231331 - 25 = 12100311231299 is a prime.
It is a super-2 number, since 2×121003112313312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12100311231311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050155615665 + 6050155615666.
It is an arithmetic number, because the mean of its divisors is an integer number (6050155615666).
Almost surely, 212100311231331 is an apocalyptic number.
12100311231331 is a deficient number, since it is larger than the sum of its proper divisors (1).
12100311231331 is an equidigital number, since it uses as much as digits as its factorization.
12100311231331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 12100311231331 its reverse (13313211300121), we get a palindrome (25413522531452).
The spelling of 12100311231331 in words is "twelve trillion, one hundred billion, three hundred eleven million, two hundred thirty-one thousand, three hundred thirty-one".
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