12100313001321 has 24 divisors (see below), whose sum is σ = 17661084884040. Its totient is φ = 7982569440000.

The previous prime is 12100313001251. The next prime is 12100313001367. The reversal of 12100313001321 is 12310031300121.

12100313001321 is a `hidden beast` number, since 1 + 2 + 10 + 0 + 31 + 300 + 1 + 321 = 666.

12100313001321 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 1048444932096 + 11051868069225 = 1023936^2 + 3324435^2 .

It is not a de Polignac number, because 12100313001321 - 2²¹ = 12100310904169 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12100313001294 and 12100313001303.

It is not an unprimeable number, because it can be changed into a prime (12100313001521) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2058526 + ... + 5332743.

It is an arithmetic number, because the mean of its divisors is an integer number (735878536835).

Almost surely, 2^{12100313001321} is an apocalyptic number.

It is an amenable number.

12100313001321 is a deficient number, since it is larger than the sum of its proper divisors (5560771882719).

12100313001321 is a wasteful number, since it uses less digits than its factorization.

12100313001321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7393177 (or 7393174 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 12100313001321 its reverse (12310031300121), we get a palindrome (24410344301442).

The spelling of 12100313001321 in words is "twelve trillion, one hundred billion, three hundred thirteen million, one thousand, three hundred twenty-one".