Base | Representation |
---|---|
bin | 11011100000110101000010… |
… | …100111001100111100001011 |
3 | 120212102210111020021120202202 |
4 | 123200311002213030330023 |
5 | 111330004104141444313 |
6 | 1105204041135150415 |
7 | 34326123604542305 |
oct | 3340650247147413 |
9 | 525383436246682 |
10 | 121003231203083 |
11 | 35612200514879 |
12 | 116a32a137540b |
13 | 526972bc6a7a8 |
14 | 21c48326a4975 |
15 | dec8898d0558 |
hex | 6e0d429ccf0b |
121003231203083 has 2 divisors, whose sum is σ = 121003231203084. Its totient is φ = 121003231203082.
The previous prime is 121003231202999. The next prime is 121003231203109. The reversal of 121003231203083 is 380302132300121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121003231203083 - 210 = 121003231202059 is a prime.
It is not a weakly prime, because it can be changed into another prime (121003231203683) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60501615601541 + 60501615601542.
It is an arithmetic number, because the mean of its divisors is an integer number (60501615601542).
Almost surely, 2121003231203083 is an apocalyptic number.
121003231203083 is a deficient number, since it is larger than the sum of its proper divisors (1).
121003231203083 is an equidigital number, since it uses as much as digits as its factorization.
121003231203083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 29.
The spelling of 121003231203083 in words is "one hundred twenty-one trillion, three billion, two hundred thirty-one million, two hundred three thousand, eighty-three".
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