Base | Representation |
---|---|
bin | 1011000000010111110100… |
… | …0111111111111111101011 |
3 | 1120211211212001000121210011 |
4 | 2300011331013333333223 |
5 | 3041230343130400323 |
6 | 41423044404432351 |
7 | 2356161415616305 |
oct | 260057507777753 |
9 | 46754761017704 |
10 | 12101022121963 |
11 | 39460185732a5 |
12 | 14353139a86b7 |
13 | 69a176bb3708 |
14 | 2db99a6a8975 |
15 | 15eb96c5b20d |
hex | b017d1fffeb |
12101022121963 has 2 divisors, whose sum is σ = 12101022121964. Its totient is φ = 12101022121962.
The previous prime is 12101022121933. The next prime is 12101022122003. The reversal of 12101022121963 is 36912122010121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12101022121963 - 213 = 12101022113771 is a prime.
It is not a weakly prime, because it can be changed into another prime (12101022121933) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050511060981 + 6050511060982.
It is an arithmetic number, because the mean of its divisors is an integer number (6050511060982).
Almost surely, 212101022121963 is an apocalyptic number.
12101022121963 is a deficient number, since it is larger than the sum of its proper divisors (1).
12101022121963 is an equidigital number, since it uses as much as digits as its factorization.
12101022121963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 31.
The spelling of 12101022121963 in words is "twelve trillion, one hundred one billion, twenty-two million, one hundred twenty-one thousand, nine hundred sixty-three".
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