12101111112113 has 2 divisors, whose sum is σ = 12101111112114. Its totient is φ = 12101111112112.

The previous prime is 12101111112019. The next prime is 12101111112149. The reversal of 12101111112113 is 31121111110121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12014493913249 + 86617198864 = 3466193^2 + 294308^2 .

It is a cyclic number.

It is not a de Polignac number, because 12101111112113 - 2¹² = 12101111108017 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12101111112091 and 12101111112100.

It is not a weakly prime, because it can be changed into another prime (12101111112313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050555556056 + 6050555556057.

It is an arithmetic number, because the mean of its divisors is an integer number (6050555556057).

Almost surely, 2^{12101111112113} is an apocalyptic number.

It is an amenable number.

12101111112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12101111112113 is an equidigital number, since it uses as much as digits as its factorization.

12101111112113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 17.

Adding to 12101111112113 its reverse (31121111110121), we get a palindrome (43222222222234).

The spelling of 12101111112113 in words is "twelve trillion, one hundred one billion, one hundred eleven million, one hundred twelve thousand, one hundred thirteen".