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121011202201202 = 260505601100601
BaseRepresentation
bin11011100000111100011101…
…101110001001011001110010
3120212110120001202010020120022
4123200330131232021121302
5111330121420230414302
61105211440121243442
734326525254112005
oct3340743556113162
9525416052106508
10121011202201202
1135615620983725
12116a4946933582
13526a3cc498021
1421c4d8b17d53c
15decba459c8a2
hex6e0f1db89672

121011202201202 has 4 divisors (see below), whose sum is σ = 181516803301806. Its totient is φ = 60505601100600.

The previous prime is 121011202201199. The next prime is 121011202201207. The reversal of 121011202201202 is 202102202110121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 120371376589321 + 639825611881 = 10971389^2 + 799891^2 .

It is a super-2 number, since 2×1210112022012022 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (121011202201207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30252800550299 + ... + 30252800550302.

Almost surely, 2121011202201202 is an apocalyptic number.

121011202201202 is a deficient number, since it is larger than the sum of its proper divisors (60505601100604).

121011202201202 is an equidigital number, since it uses as much as digits as its factorization.

121011202201202 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60505601100603.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 121011202201202 its reverse (202102202110121), we get a palindrome (323113404311323).

The spelling of 121011202201202 in words is "one hundred twenty-one trillion, eleven billion, two hundred two million, two hundred one thousand, two hundred two".

Divisors: 1 2 60505601100601 121011202201202