Base | Representation |
---|---|
bin | 10001100111000000010… |
… | …011101111010001001001 |
3 | 11021200111210121121021111 |
4 | 101213000103233101021 |
5 | 124311302211204433 |
6 | 2323530132210321 |
7 | 153266465032561 |
oct | 21470023572111 |
9 | 4250453547244 |
10 | 1210112209993 |
11 | 427229882135 |
12 | 1766401699a1 |
13 | 8a16160240b |
14 | 427d9539da1 |
15 | 21727860dcd |
hex | 119c04ef449 |
1210112209993 has 2 divisors, whose sum is σ = 1210112209994. Its totient is φ = 1210112209992.
The previous prime is 1210112209979. The next prime is 1210112210051. The reversal of 1210112209993 is 3999022110121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1198506026169 + 11606183824 = 1094763^2 + 107732^2 .
It is a cyclic number.
It is not a de Polignac number, because 1210112209993 - 213 = 1210112201801 is a prime.
It is not a weakly prime, because it can be changed into another prime (1210112209903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605056104996 + 605056104997.
It is an arithmetic number, because the mean of its divisors is an integer number (605056104997).
Almost surely, 21210112209993 is an apocalyptic number.
It is an amenable number.
1210112209993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210112209993 is an equidigital number, since it uses as much as digits as its factorization.
1210112209993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 40.
The spelling of 1210112209993 in words is "one trillion, two hundred ten billion, one hundred twelve million, two hundred nine thousand, nine hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •