Base | Representation |
---|---|
bin | 10001100111000000110… |
… | …010001110011110000010 |
3 | 11021200112100122122101222 |
4 | 101213000302032132002 |
5 | 124311311232431424 |
6 | 2323531015355042 |
7 | 153266623000325 |
oct | 21470062163602 |
9 | 4250470578358 |
10 | 1210120202114 |
11 | 42723334079a |
12 | 176642982a82 |
13 | 8a163170095 |
14 | 427da61a7bc |
15 | 217283dde5e |
hex | 119c0c8e782 |
1210120202114 has 4 divisors (see below), whose sum is σ = 1815180303174. Its totient is φ = 605060101056.
The previous prime is 1210120202029. The next prime is 1210120202119. The reversal of 1210120202114 is 4112020210121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 656234466889 + 553885735225 = 810083^2 + 744235^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1210120202092 and 1210120202101.
It is not an unprimeable number, because it can be changed into a prime (1210120202119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 302530050527 + ... + 302530050530.
Almost surely, 21210120202114 is an apocalyptic number.
1210120202114 is a deficient number, since it is larger than the sum of its proper divisors (605060101060).
1210120202114 is an equidigital number, since it uses as much as digits as its factorization.
1210120202114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 605060101059.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 1210120202114 its reverse (4112020210121), we get a palindrome (5322140412235).
The spelling of 1210120202114 in words is "one trillion, two hundred ten billion, one hundred twenty million, two hundred two thousand, one hundred fourteen".
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