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1210121313017 is a prime number
BaseRepresentation
bin10001100111000000110…
…110011101101011111001
311021200112102202002021112
4101213000312131223321
5124311312024004032
62323531055250105
7153266635305161
oct21470066355371
94250472662245
101210121313017
11427233a2a3a1
12176643219935
138a16346b916
14427da8295a1
152172855d1b2
hex119c0d9daf9

1210121313017 has 2 divisors, whose sum is σ = 1210121313018. Its totient is φ = 1210121313016.

The previous prime is 1210121313001. The next prime is 1210121313041. The reversal of 1210121313017 is 7103131210121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1185596500201 + 24524812816 = 1088851^2 + 156604^2 .

It is a cyclic number.

It is not a de Polignac number, because 1210121313017 - 24 = 1210121313001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1210121312983 and 1210121313001.

It is not a weakly prime, because it can be changed into another prime (1210121333017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605060656508 + 605060656509.

It is an arithmetic number, because the mean of its divisors is an integer number (605060656509).

Almost surely, 21210121313017 is an apocalyptic number.

It is an amenable number.

1210121313017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210121313017 is an equidigital number, since it uses as much as digits as its factorization.

1210121313017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 23.

Adding to 1210121313017 its reverse (7103131210121), we get a palindrome (8313252523138).

The spelling of 1210121313017 in words is "one trillion, two hundred ten billion, one hundred twenty-one million, three hundred thirteen thousand, seventeen".