Base | Representation |
---|---|
bin | 11011100000111110001111… |
… | …100111010100010001001011 |
3 | 120212110201222220122120000121 |
4 | 123200332033213110101023 |
5 | 111330134323412411243 |
6 | 1105212353500444111 |
7 | 34326623515542556 |
oct | 3340761747242113 |
9 | 525421886576017 |
10 | 121013113013323 |
11 | 356164115440a3 |
12 | 116a519a849637 |
13 | 526a645315c9b |
14 | 21c50ccc5d69d |
15 | decc671e41ed |
hex | 6e0f8f9d444b |
121013113013323 has 4 divisors (see below), whose sum is σ = 121013268061320. Its totient is φ = 121012957965328.
The previous prime is 121013113013321. The next prime is 121013113013327. The reversal of 121013113013323 is 323310311310121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 121013113013323 - 21 = 121013113013321 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (121013113013321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76347313 + ... + 77916226.
It is an arithmetic number, because the mean of its divisors is an integer number (30253317015330).
Almost surely, 2121013113013323 is an apocalyptic number.
121013113013323 is a deficient number, since it is larger than the sum of its proper divisors (155047997).
121013113013323 is an equidigital number, since it uses as much as digits as its factorization.
121013113013323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 155047996.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 121013113013323 its reverse (323310311310121), we get a palindrome (444323424323444).
The spelling of 121013113013323 in words is "one hundred twenty-one trillion, thirteen billion, one hundred thirteen million, thirteen thousand, three hundred twenty-three".
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