12102021430413 has 4 divisors (see below), whose sum is σ = 16136028573888. Its totient is φ = 8068014286940.

The previous prime is 12102021430399. The next prime is 12102021430439. The reversal of 12102021430413 is 31403412020121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12102021430413 - 2⁵ = 12102021430381 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12102021430453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2017003571733 + ... + 2017003571738.

It is an arithmetic number, because the mean of its divisors is an integer number (4034007143472).

Almost surely, 2^{12102021430413} is an apocalyptic number.

It is an amenable number.

12102021430413 is a deficient number, since it is larger than the sum of its proper divisors (4034007143475).

12102021430413 is an equidigital number, since it uses as much as digits as its factorization.

12102021430413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4034007143474.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 12102021430413 its reverse (31403412020121), we get a palindrome (43505433450534).

The spelling of 12102021430413 in words is "twelve trillion, one hundred two billion, twenty-one million, four hundred thirty thousand, four hundred thirteen".