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121021104433 is a prime number
BaseRepresentation
bin111000010110101101…
…0111000000100110001
3102120101011120002110011
41300231122320010301
53440322400320213
6131332450134521
711513005262155
oct1605532700461
9376334502404
10121021104433
1147363292a89
121b555881441
13b548903588
145c00bc9065
15323495503d
hex1c2d6b8131

121021104433 has 2 divisors, whose sum is σ = 121021104434. Its totient is φ = 121021104432.

The previous prime is 121021104401. The next prime is 121021104467. The reversal of 121021104433 is 334401120121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117298030144 + 3723074289 = 342488^2 + 61017^2 .

It is a cyclic number.

It is not a de Polignac number, because 121021104433 - 25 = 121021104401 is a prime.

It is a super-2 number, since 2×1210211044332 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (121021104493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60510552216 + 60510552217.

It is an arithmetic number, because the mean of its divisors is an integer number (60510552217).

Almost surely, 2121021104433 is an apocalyptic number.

It is an amenable number.

121021104433 is a deficient number, since it is larger than the sum of its proper divisors (1).

121021104433 is an equidigital number, since it uses as much as digits as its factorization.

121021104433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 121021104433 its reverse (334401120121), we get a palindrome (455422224554).

The spelling of 121021104433 in words is "one hundred twenty-one billion, twenty-one million, one hundred four thousand, four hundred thirty-three".