121021220011021 has 4 divisors (see below), whose sum is σ = 132023149102944. Its totient is φ = 110019290919100.

The previous prime is 121021220011019. The next prime is 121021220011037. The reversal of 121021220011021 is 120110022120121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121021220011021 - 2¹ = 121021220011019 is a prime.

It is a super-2 number, since 2×121021220011021² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121021220010986 and 121021220011004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121021220011091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5500964545945 + ... + 5500964545966.

It is an arithmetic number, because the mean of its divisors is an integer number (33005787275736).

Almost surely, 2^{121021220011021} is an apocalyptic number.

121021220011021 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

121021220011021 is a deficient number, since it is larger than the sum of its proper divisors (11001929091923).

121021220011021 is a wasteful number, since it uses less digits than its factorization.

121021220011021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11001929091922.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 121021220011021 its reverse (120110022120121), we get a palindrome (241131242131142).

The spelling of 121021220011021 in words is "one hundred twenty-one trillion, twenty-one billion, two hundred twenty million, eleven thousand, twenty-one".