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12102212209993 is a prime number
BaseRepresentation
bin1011000000011100010000…
…0011110100110101001001
31120211221220222101100122121
42300013010003310311021
53041240312311204433
641423402440251241
72356233046322563
oct260070403646511
946757828340577
1012102212209993
11394657931a024
1214355a6470b21
1369a306617409
142dba70778333
1515ec16489c2d
hexb01c40f4d49

12102212209993 has 2 divisors, whose sum is σ = 12102212209994. Its totient is φ = 12102212209992.

The previous prime is 12102212209987. The next prime is 12102212210009. The reversal of 12102212209993 is 39990221220121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9056199459904 + 3046012750089 = 3009352^2 + 1745283^2 .

It is a cyclic number.

It is not a de Polignac number, because 12102212209993 - 221 = 12102210112841 is a prime.

It is not a weakly prime, because it can be changed into another prime (12102212209193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051106104996 + 6051106104997.

It is an arithmetic number, because the mean of its divisors is an integer number (6051106104997).

Almost surely, 212102212209993 is an apocalyptic number.

It is an amenable number.

12102212209993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12102212209993 is an equidigital number, since it uses as much as digits as its factorization.

12102212209993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69984, while the sum is 43.

The spelling of 12102212209993 in words is "twelve trillion, one hundred two billion, two hundred twelve million, two hundred nine thousand, nine hundred ninety-three".