Base | Representation |
---|---|
bin | 11011100001001111001110… |
… | …010010100101001100010111 |
3 | 120212112111001111020112112222 |
4 | 123201033032102211030113 |
5 | 111330434143132131130 |
6 | 1105225010530532555 |
7 | 34331140354062644 |
oct | 3341171622451427 |
9 | 525474044215488 |
10 | 121031344411415 |
11 | 35623117704349 |
12 | 116a882843715b |
13 | 526c28c474cc9 |
14 | 21c5d3c2c2dcb |
15 | ded482a59ce5 |
hex | 6e13ce4a5317 |
121031344411415 has 32 divisors (see below), whose sum is σ = 146956915392000. Its totient is φ = 95685501149568.
The previous prime is 121031344411357. The next prime is 121031344411459. The reversal of 121031344411415 is 514114443130121.
It is a cyclic number.
It is not a de Polignac number, because 121031344411415 - 210 = 121031344410391 is a prime.
It is a super-4 number, since 4×1210313444114154 (a number of 57 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 671384822 + ... + 671565068.
It is an arithmetic number, because the mean of its divisors is an integer number (4592403606000).
Almost surely, 2121031344411415 is an apocalyptic number.
121031344411415 is a deficient number, since it is larger than the sum of its proper divisors (25925570980585).
121031344411415 is a wasteful number, since it uses less digits than its factorization.
121031344411415 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 184839.
The product of its (nonzero) digits is 23040, while the sum is 35.
Adding to 121031344411415 its reverse (514114443130121), we get a palindrome (635145787541536).
The spelling of 121031344411415 in words is "one hundred twenty-one trillion, thirty-one billion, three hundred forty-four million, four hundred eleven thousand, four hundred fifteen".
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