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121032213297953 is a prime number
BaseRepresentation
bin11011100001010000000010…
…000101000111101100100001
3120212112120022001012112210212
4123201100002011013230201
5111330442433101013303
61105225233050103505
734331201034354566
oct3341200205075441
9525476261175725
10121032213297953
11356235231156a1
12116a8a2b41ab95
13526c39a496959
1421c5dc186086d
15ded4d3e8cad8
hex6e1402147b21

121032213297953 has 2 divisors, whose sum is σ = 121032213297954. Its totient is φ = 121032213297952.

The previous prime is 121032213297943. The next prime is 121032213297959. The reversal of 121032213297953 is 359792312230121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117707050106944 + 3325163191009 = 10849288^2 + 1823503^2 .

It is a cyclic number.

It is not a de Polignac number, because 121032213297953 - 214 = 121032213281569 is a prime.

It is a super-3 number, since 3×1210322132979533 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (121032213297959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60516106648976 + 60516106648977.

It is an arithmetic number, because the mean of its divisors is an integer number (60516106648977).

Almost surely, 2121032213297953 is an apocalyptic number.

It is an amenable number.

121032213297953 is a deficient number, since it is larger than the sum of its proper divisors (1).

121032213297953 is an equidigital number, since it uses as much as digits as its factorization.

121032213297953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1224720, while the sum is 50.

The spelling of 121032213297953 in words is "one hundred twenty-one trillion, thirty-two billion, two hundred thirteen million, two hundred ninety-seven thousand, nine hundred fifty-three".