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121040112111 = 340346704037
BaseRepresentation
bin111000010111010001…
…1011000100111101111
3102120102111022210002020
41300232203120213233
53440342232041421
6131334405401223
711513325656142
oct1605643304757
9376374283066
10121040112111
1147372a95806
121b560109213
13b54c82a119
145c03536059
15323645bdc6
hex1c2e8d89ef

121040112111 has 4 divisors (see below), whose sum is σ = 161386816152. Its totient is φ = 80693408072.

The previous prime is 121040112103. The next prime is 121040112119. The reversal of 121040112111 is 111211040121.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (121040112103) and next prime (121040112119).

It is a cyclic number.

It is not a de Polignac number, because 121040112111 - 23 = 121040112103 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121040112119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20173352016 + ... + 20173352021.

It is an arithmetic number, because the mean of its divisors is an integer number (40346704038).

Almost surely, 2121040112111 is an apocalyptic number.

121040112111 is a deficient number, since it is larger than the sum of its proper divisors (40346704041).

121040112111 is an equidigital number, since it uses as much as digits as its factorization.

121040112111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40346704040.

The product of its (nonzero) digits is 16, while the sum is 15.

Adding to 121040112111 its reverse (111211040121), we get a palindrome (232251152232).

The spelling of 121040112111 in words is "one hundred twenty-one billion, forty million, one hundred twelve thousand, one hundred eleven".

Divisors: 1 3 40346704037 121040112111