Base | Representation |
---|---|
bin | 10110100010111011… |
… | …00001111101011110 |
3 | 1011020120000200221001 |
4 | 23101131201331132 |
5 | 144242123122024 |
6 | 5321025100514 |
7 | 605644162066 |
oct | 132135417536 |
9 | 34216020831 |
10 | 12104114014 |
11 | 5151503013 |
12 | 241978773a |
13 | 11ab8b8a55 |
14 | 82b7a03a6 |
15 | 4ac989244 |
hex | 2d1761f5e |
12104114014 has 4 divisors (see below), whose sum is σ = 18156171024. Its totient is φ = 6052057006.
The previous prime is 12104113969. The next prime is 12104114041. The reversal of 12104114014 is 41041140121.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×121041140143 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 12104113982 and 12104114000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3026028502 + ... + 3026028505.
It is an arithmetic number, because the mean of its divisors is an integer number (4539042756).
Almost surely, 212104114014 is an apocalyptic number.
12104114014 is a deficient number, since it is larger than the sum of its proper divisors (6052057010).
12104114014 is an equidigital number, since it uses as much as digits as its factorization.
12104114014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6052057009.
The product of its (nonzero) digits is 128, while the sum is 19.
Adding to 12104114014 its reverse (41041140121), we get a palindrome (53145254135).
The spelling of 12104114014 in words is "twelve billion, one hundred four million, one hundred fourteen thousand, fourteen".
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