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12104114014 = 26052057007
BaseRepresentation
bin10110100010111011…
…00001111101011110
31011020120000200221001
423101131201331132
5144242123122024
65321025100514
7605644162066
oct132135417536
934216020831
1012104114014
115151503013
12241978773a
1311ab8b8a55
1482b7a03a6
154ac989244
hex2d1761f5e

12104114014 has 4 divisors (see below), whose sum is σ = 18156171024. Its totient is φ = 6052057006.

The previous prime is 12104113969. The next prime is 12104114041. The reversal of 12104114014 is 41041140121.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×121041140143 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 12104113982 and 12104114000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3026028502 + ... + 3026028505.

It is an arithmetic number, because the mean of its divisors is an integer number (4539042756).

Almost surely, 212104114014 is an apocalyptic number.

12104114014 is a deficient number, since it is larger than the sum of its proper divisors (6052057010).

12104114014 is an equidigital number, since it uses as much as digits as its factorization.

12104114014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6052057009.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 12104114014 its reverse (41041140121), we get a palindrome (53145254135).

The spelling of 12104114014 in words is "twelve billion, one hundred four million, one hundred fourteen thousand, fourteen".

Divisors: 1 2 6052057007 12104114014