Base | Representation |
---|---|
bin | 10110100010111101… |
… | …01000111001010001 |
3 | 1011020120120110111001 |
4 | 23101132220321101 |
5 | 144242211421221 |
6 | 5321035222001 |
7 | 605646512134 |
oct | 132136507121 |
9 | 34216513431 |
10 | 12104404561 |
11 | 5151691337 |
12 | 24198a7901 |
13 | 11ab98b082 |
14 | 82b83821b |
15 | 4ac9e5391 |
hex | 2d17a8e51 |
12104404561 has 2 divisors, whose sum is σ = 12104404562. Its totient is φ = 12104404560.
The previous prime is 12104404531. The next prime is 12104404567. The reversal of 12104404561 is 16540440121.
12104404561 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6621890625 + 5482513936 = 81375^2 + 74044^2 .
It is a cyclic number.
It is not a de Polignac number, because 12104404561 - 231 = 9956920913 is a prime.
It is not a weakly prime, because it can be changed into another prime (12104404567) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6052202280 + 6052202281.
It is an arithmetic number, because the mean of its divisors is an integer number (6052202281).
Almost surely, 212104404561 is an apocalyptic number.
It is an amenable number.
12104404561 is a deficient number, since it is larger than the sum of its proper divisors (1).
12104404561 is an equidigital number, since it uses as much as digits as its factorization.
12104404561 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 28.
Adding to 12104404561 its reverse (16540440121), we get a palindrome (28644844682).
The spelling of 12104404561 in words is "twelve billion, one hundred four million, four hundred four thousand, five hundred sixty-one".
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