Search a number
-
+
12106543133 = 43927577547
BaseRepresentation
bin10110100011001101…
…10011000000011101
31011020201121010001102
423101212303000131
5144243233340013
65321153122445
7606003630056
oct132146630035
934221533042
1012106543133
115152912053
12241a559425
1311ac2595b9
1482bc3372d
154accb8d58
hex2d19b301d

12106543133 has 4 divisors (see below), whose sum is σ = 12134121120. Its totient is φ = 12078965148.

The previous prime is 12106543123. The next prime is 12106543147. The reversal of 12106543133 is 33134560121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12106543133 - 212 = 12106539037 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12106543096 and 12106543105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12106543123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13788335 + ... + 13789212.

It is an arithmetic number, because the mean of its divisors is an integer number (3033530280).

Almost surely, 212106543133 is an apocalyptic number.

It is an amenable number.

12106543133 is a deficient number, since it is larger than the sum of its proper divisors (27577987).

12106543133 is an equidigital number, since it uses as much as digits as its factorization.

12106543133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27577986.

The product of its (nonzero) digits is 6480, while the sum is 29.

The spelling of 12106543133 in words is "twelve billion, one hundred six million, five hundred forty-three thousand, one hundred thirty-three".

Divisors: 1 439 27577547 12106543133