Base | Representation |
---|---|
bin | 10001100111101001001… |
… | …010011100110110111011 |
3 | 11021202021120101010001112 |
4 | 101213221022130312323 |
5 | 124314203144004042 |
6 | 2324122135310535 |
7 | 153322460065253 |
oct | 21475112346673 |
9 | 4252246333045 |
10 | 1210797641147 |
11 | 427550780766 |
12 | 1767b181b44b |
13 | 8a240610493 |
14 | 428625a0963 |
15 | 21767b06982 |
hex | 119e929cdbb |
1210797641147 has 2 divisors, whose sum is σ = 1210797641148. Its totient is φ = 1210797641146.
The previous prime is 1210797641087. The next prime is 1210797641153. The reversal of 1210797641147 is 7411467970121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1210797641147 - 28 = 1210797640891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1210797641095 and 1210797641104.
It is not a weakly prime, because it can be changed into another prime (1210797641167) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605398820573 + 605398820574.
It is an arithmetic number, because the mean of its divisors is an integer number (605398820574).
Almost surely, 21210797641147 is an apocalyptic number.
1210797641147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210797641147 is an equidigital number, since it uses as much as digits as its factorization.
1210797641147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 592704, while the sum is 50.
The spelling of 1210797641147 in words is "one trillion, two hundred ten billion, seven hundred ninety-seven million, six hundred forty-one thousand, one hundred forty-seven".
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