Base | Representation |
---|---|
bin | 1011000000111001010011… |
… | …0110000111010001010011 |
3 | 1120212201001102100012022201 |
4 | 2300032110312013101103 |
5 | 3041402300031132242 |
6 | 41431132314344031 |
7 | 2356630223530366 |
oct | 260162466072123 |
9 | 46781042305281 |
10 | 12110010020947 |
11 | 394990aa49893 |
12 | 1437001a2b017 |
13 | 69ac79cb7a37 |
14 | 2dc1b02500dd |
15 | 160020d474b7 |
hex | b0394d87453 |
12110010020947 has 2 divisors, whose sum is σ = 12110010020948. Its totient is φ = 12110010020946.
The previous prime is 12110010020939. The next prime is 12110010020959. The reversal of 12110010020947 is 74902001001121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12110010020947 - 23 = 12110010020939 is a prime.
It is not a weakly prime, because it can be changed into another prime (12110010420947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055005010473 + 6055005010474.
It is an arithmetic number, because the mean of its divisors is an integer number (6055005010474).
Almost surely, 212110010020947 is an apocalyptic number.
12110010020947 is a deficient number, since it is larger than the sum of its proper divisors (1).
12110010020947 is an equidigital number, since it uses as much as digits as its factorization.
12110010020947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 28.
The spelling of 12110010020947 in words is "twelve trillion, one hundred ten billion, ten million, twenty thousand, nine hundred forty-seven".
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