Base | Representation |
---|---|
bin | 11011100010001111010001… |
… | …000110010011001010011100 |
3 | 120212210001112221201012100110 |
4 | 123202033101012103022130 |
5 | 111333101011404001340 |
6 | 1105320342321330020 |
7 | 34336123433330412 |
oct | 3342172106231234 |
9 | 525701487635313 |
10 | 121100111000220 |
11 | 3564a2a564a320 |
12 | 116ba01a196910 |
13 | 52758cb1ca641 |
14 | 21c93c318d2b2 |
15 | e00159c30680 |
hex | 6e23d119329c |
121100111000220 has 192 divisors, whose sum is σ = 377710046009856. Its totient is φ = 28744088555520.
The previous prime is 121100111000203. The next prime is 121100111000221. The reversal of 121100111000220 is 22000111001121.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a junction number, because it is equal to n+sod(n) for n = 121100111000196 and 121100111000205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121100111000221) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2572674 + ... + 15773993.
It is an arithmetic number, because the mean of its divisors is an integer number (1967239822968).
Almost surely, 2121100111000220 is an apocalyptic number.
121100111000220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 121100111000220, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (188855023004928).
121100111000220 is an abundant number, since it is smaller than the sum of its proper divisors (256609935009636).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121100111000220 is a wasteful number, since it uses less digits than its factorization.
121100111000220 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18346900 (or 18346898 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 12.
Adding to 121100111000220 its reverse (22000111001121), we get a palindrome (143100222001341).
Subtracting from 121100111000220 its reverse (22000111001121), we obtain a palindrome (99099999999099).
It can be divided in two parts, 1211001 and 11000220, that added together give a palindrome (12211221).
The spelling of 121100111000220 in words is "one hundred twenty-one trillion, one hundred billion, one hundred eleven million, two hundred twenty", and thus it is an aban number.
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