Base | Representation |
---|---|
bin | 11011100010001111010001… |
… | …110000101011110011011001 |
3 | 120212210001120201121200201222 |
4 | 123202033101300223303121 |
5 | 111333101022230024233 |
6 | 1105320343355421425 |
7 | 34336123626635051 |
oct | 3342172160536331 |
9 | 525701521550658 |
10 | 121100122111193 |
11 | 3564a300949145 |
12 | 116ba021a54875 |
13 | 52759005baa94 |
14 | 21c93c4842561 |
15 | e0015abc7898 |
hex | 6e23d1c2bcd9 |
121100122111193 has 2 divisors, whose sum is σ = 121100122111194. Its totient is φ = 121100122111192.
The previous prime is 121100122111159. The next prime is 121100122111261. The reversal of 121100122111193 is 391111221001121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 74205182463049 + 46894939648144 = 8614243^2 + 6847988^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121100122111193 is a prime.
It is not a weakly prime, because it can be changed into another prime (121100122113193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60550061055596 + 60550061055597.
It is an arithmetic number, because the mean of its divisors is an integer number (60550061055597).
Almost surely, 2121100122111193 is an apocalyptic number.
It is an amenable number.
121100122111193 is a deficient number, since it is larger than the sum of its proper divisors (1).
121100122111193 is an equidigital number, since it uses as much as digits as its factorization.
121100122111193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 26.
The spelling of 121100122111193 in words is "one hundred twenty-one trillion, one hundred billion, one hundred twenty-two million, one hundred eleven thousand, one hundred ninety-three".
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