Base | Representation |
---|---|
bin | 11011100010001111010110… |
… | …011110011001000101001111 |
3 | 120212210001210020102220221002 |
4 | 123202033112132121011033 |
5 | 111333101203001430444 |
6 | 1105320355302530515 |
7 | 34336125610123355 |
oct | 3342172636310517 |
9 | 525701706386832 |
10 | 121100201201999 |
11 | 3564a341559248 |
12 | 116ba044436a3b |
13 | 5275913ac0386 |
14 | 21c93d114d7d5 |
15 | e00162aebd4e |
hex | 6e23d679914f |
121100201201999 has 4 divisors (see below), whose sum is σ = 121153292042160. Its totient is φ = 121047110361840.
The previous prime is 121100201201951. The next prime is 121100201202011. The reversal of 121100201201999 is 999102102001121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 121100201201999 - 212 = 121100201197903 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121100201201929) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26545416659 + ... + 26545421220.
It is an arithmetic number, because the mean of its divisors is an integer number (30288323010540).
Almost surely, 2121100201201999 is an apocalyptic number.
121100201201999 is a deficient number, since it is larger than the sum of its proper divisors (53090840161).
121100201201999 is an equidigital number, since it uses as much as digits as its factorization.
121100201201999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53090840160.
The product of its (nonzero) digits is 5832, while the sum is 38.
The spelling of 121100201201999 in words is "one hundred twenty-one trillion, one hundred billion, two hundred one million, two hundred one thousand, nine hundred ninety-nine".
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