12110020123 has 4 divisors (see below), whose sum is σ = 12290766760. Its totient is φ = 11929273488.

The previous prime is 12110020093. The next prime is 12110020163. The reversal of 12110020123 is 32102001121.

12110020123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32102001121 = 23081 ⋅1390841.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12110020123 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12110020163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90373218 + ... + 90373351.

It is an arithmetic number, because the mean of its divisors is an integer number (3072691690).

Almost surely, 2^12110020123 is an apocalyptic number.

12110020123 is a deficient number, since it is larger than the sum of its proper divisors (180746637).

12110020123 is an equidigital number, since it uses as much as digits as its factorization.

12110020123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 180746636.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 12110020123 its reverse (32102001121), we get a palindrome (44212021244).

The spelling of 12110020123 in words is "twelve billion, one hundred ten million, twenty thousand, one hundred twenty-three".