Base | Representation |
---|---|
bin | 10110100011101000… |
… | …00011111001000011 |
3 | 1011020222010202122022 |
4 | 23101310003321003 |
5 | 144300131121123 |
6 | 5321355432055 |
7 | 606045321143 |
oct | 132164037103 |
9 | 34228122568 |
10 | 12110020163 |
11 | 515487742a |
12 | 241b75562b |
13 | 11acba6107 |
14 | 82c49a923 |
15 | 4ad2541c8 |
hex | 2d1d03e43 |
12110020163 has 2 divisors, whose sum is σ = 12110020164. Its totient is φ = 12110020162.
The previous prime is 12110020093. The next prime is 12110020199. The reversal of 12110020163 is 36102001121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12110020163 is a prime.
It is not a weakly prime, because it can be changed into another prime (12110020963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055010081 + 6055010082.
It is an arithmetic number, because the mean of its divisors is an integer number (6055010082).
Almost surely, 212110020163 is an apocalyptic number.
12110020163 is a deficient number, since it is larger than the sum of its proper divisors (1).
12110020163 is an equidigital number, since it uses as much as digits as its factorization.
12110020163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 12110020163 its reverse (36102001121), we get a palindrome (48212021284).
The spelling of 12110020163 in words is "twelve billion, one hundred ten million, twenty thousand, one hundred sixty-three".
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