12110031340000 has 240 divisors, whose sum is σ = 32519360910960. Its totient is φ = 4401146880000.

The previous prime is 12110031339983. The next prime is 12110031340031. The reversal of 12110031340000 is 4313001121.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 412045306 + ... + 412074694.

It is an arithmetic number, because the mean of its divisors is an integer number (135497337129).

Almost surely, 2^{12110031340000} is an apocalyptic number.

12110031340000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12110031340000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16259680455480).

12110031340000 is an abundant number, since it is smaller than the sum of its proper divisors (20409329570960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12110031340000 is a wasteful number, since it uses less digits than its factorization.

12110031340000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31303 (or 31280 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 12110031340000 its reverse (4313001121), we get a palindrome (12114344341121).

The spelling of 12110031340000 in words is "twelve trillion, one hundred ten billion, thirty-one million, three hundred forty thousand".