12110064433135 has 8 divisors (see below), whose sum is σ = 14532222676896. Its totient is φ = 9687954641760.

The previous prime is 12110064433123. The next prime is 12110064433139. The reversal of 12110064433135 is 53133446001121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12110064433135 - 2⁴³ = 3313971410927 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12110064433135.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12110064433139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11560944 + ... + 12564853.

It is an arithmetic number, because the mean of its divisors is an integer number (1816527834612).

Almost surely, 2^{12110064433135} is an apocalyptic number.

12110064433135 is a deficient number, since it is larger than the sum of its proper divisors (2422158243761).

12110064433135 is a wasteful number, since it uses less digits than its factorization.

12110064433135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24226193.

The product of its (nonzero) digits is 25920, while the sum is 34.

The spelling of 12110064433135 in words is "twelve trillion, one hundred ten billion, sixty-four million, four hundred thirty-three thousand, one hundred thirty-five".