Base | Representation |
---|---|
bin | 10001100111110101111… |
… | …001100010110111001110 |
3 | 11021202211110102202212122 |
4 | 101213311321202313032 |
5 | 124320122344004402 |
6 | 2324155251132542 |
7 | 153330663214463 |
oct | 21476571426716 |
9 | 4252743382778 |
10 | 1211011313102 |
11 | 427650351658 |
12 | 1768512a4152 |
13 | 8a2759737a6 |
14 | 42882b0166a |
15 | 2177b761ca2 |
hex | 119f5e62dce |
1211011313102 has 4 divisors (see below), whose sum is σ = 1816516969656. Its totient is φ = 605505656550.
The previous prime is 1211011313069. The next prime is 1211011313111. The reversal of 1211011313102 is 2013131101121.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×12110113131022 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 302752828274 + ... + 302752828277.
It is an arithmetic number, because the mean of its divisors is an integer number (454129242414).
Almost surely, 21211011313102 is an apocalyptic number.
1211011313102 is a deficient number, since it is larger than the sum of its proper divisors (605505656554).
1211011313102 is an equidigital number, since it uses as much as digits as its factorization.
1211011313102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 605505656553.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 1211011313102 its reverse (2013131101121), we get a palindrome (3224142414223).
The spelling of 1211011313102 in words is "one trillion, two hundred eleven billion, eleven million, three hundred thirteen thousand, one hundred two".
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