Base | Representation |
---|---|
bin | 10001100111110101111… |
… | …001100100100010000011 |
3 | 11021202211110110010020212 |
4 | 101213311321210202003 |
5 | 124320122344214224 |
6 | 2324155251224335 |
7 | 153330663243431 |
oct | 21476571444203 |
9 | 4252743403225 |
10 | 1211011319939 |
11 | 427650356803 |
12 | 1768512a80ab |
13 | 8a275976935 |
14 | 42882b03d51 |
15 | 2177b763d0e |
hex | 119f5e64883 |
1211011319939 has 2 divisors, whose sum is σ = 1211011319940. Its totient is φ = 1211011319938.
The previous prime is 1211011319927. The next prime is 1211011319963. The reversal of 1211011319939 is 9399131101121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1211011319939 - 240 = 111499692163 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1211011319896 and 1211011319905.
It is not a weakly prime, because it can be changed into another prime (1211011319839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605505659969 + 605505659970.
It is an arithmetic number, because the mean of its divisors is an integer number (605505659970).
Almost surely, 21211011319939 is an apocalyptic number.
1211011319939 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211011319939 is an equidigital number, since it uses as much as digits as its factorization.
1211011319939 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13122, while the sum is 41.
The spelling of 1211011319939 in words is "one trillion, two hundred eleven billion, eleven million, three hundred nineteen thousand, nine hundred thirty-nine".
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