Base | Representation |
---|---|
bin | 111000011001000111… |
… | …1011110000000011001 |
3 | 102120120210210000111221 |
4 | 1300302033132000121 |
5 | 3441004103001103 |
6 | 131344500052041 |
7 | 11515010005561 |
oct | 1606217360031 |
9 | 376523700457 |
10 | 121102000153 |
11 | 473a4a16152 |
12 | 1b578994021 |
13 | b55c5b8574 |
14 | 5c0b845da1 |
15 | 323bad41bd |
hex | 1c323de019 |
121102000153 has 2 divisors, whose sum is σ = 121102000154. Its totient is φ = 121102000152.
The previous prime is 121102000127. The next prime is 121102000171. The reversal of 121102000153 is 351000201121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 119862748944 + 1239251209 = 346212^2 + 35203^2 .
It is a cyclic number.
It is not a de Polignac number, because 121102000153 - 217 = 121101869081 is a prime.
It is not a weakly prime, because it can be changed into another prime (121102000183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60551000076 + 60551000077.
It is an arithmetic number, because the mean of its divisors is an integer number (60551000077).
Almost surely, 2121102000153 is an apocalyptic number.
It is an amenable number.
121102000153 is a deficient number, since it is larger than the sum of its proper divisors (1).
121102000153 is an equidigital number, since it uses as much as digits as its factorization.
121102000153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60, while the sum is 16.
Adding to 121102000153 its reverse (351000201121), we get a palindrome (472102201274).
The spelling of 121102000153 in words is "one hundred twenty-one billion, one hundred two million, one hundred fifty-three", and thus it is an aban number.
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